This is a simple algorithm of calling functions or methods.
The answer will be -12. How? Let's see.
In any algorithm of calling functions firstly, we should see from where the function is being called.
In the above algorithm Line-11 is calling the function F.
And, while returning the result it is calling the function G.
So first we will see Line 11.
1. ans <-- -3*F(4,2)
The function F is called with parameters 4 and 2. Then the result of this function will be multiplied with -3 for the answer.
2. In Line 1,
Procedure F(x,y)
The function F has 2 values x=4 and y=2. These are the values that we passed in the parameters while calling Function F in line 11.
3. The return statement in function F calls another function G with the same parameters.
In function G,
Return x-y
means it will return the difference of x and y where x=4 and y=2 as passed in parameters.
So 4-2=2. It will return 2 to the function F.
4. Now we will get back to Function F return statement
Return 2*G(x,y)
and G(x,y)=2 that we just solved.
So, 2*2=4 which will be returned to Line 11.
5. Coming back to Line 11
-3*4=-12 which will be allocated to ans
In Line 12 it displays the ans which is -12.
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