Question

Starting to understand concept of ideal transformers although still struggling with converting the 2cos280tV to 2<0(polar form) please explain, or for instance converting a Voltage source in the form 5sin120pitV to 5< 0(polar form)(Not part of this question just example.)

Calculate the average power delivered to the 400 mΩ and 21 Ω resistors, respectively, in the circuit of fig. 13.65 3Ω W:100 40m 2i 21 D FIGURE 13.65

Answer 1

Given circuit Given that N_1/ N_2 = 1/100 For finding I_1 first converting the impedance in the secondary to primary Z^1_1 = z_2 (N_1/ N_2)^2 z_2 = 400 m + 21 = 0.4 + 21 = 21.4 ohm z^1_1 = 21.4 (1/100)^2 z61_1 = 2.14 m ohm Equivalent circuit in the primary \r\n i_1 = 2 angle 0 degree/3 + 2.14 m i_1 = 0.666A we know current transformation ratio i_1/i_2 = N_2/ N_1 i_2 = i_1 (N_1/ N_2) = 0.666 (1/100) i_2 = 6.66 mA Average power delivered to the 400 m ohm p_del = i^2_2 R = (6.66 m)^2 (400 m)p_del = 1.774 times 10^-5 watts = 0.0177 milliwatts Average power delivered to 21 ohm p_del = i^2_2 r = (6.66 M)^2 times 21 p_del = 9.31 times 10^-4 watts p_del = 0.931 m watts m = milli