Question

Projectile Motion and Motion Diagrams 3.2 A ball rolls down a long ramp to a shoot where it is released as a projectile with an initial speed of 20 m/s at an angel of 42° above horizontal and 4.0 m above the ground. See diagram. BALL RAMP GROUND A. Draw a complete motiongrantee the motion of the ball from it leaving the shoot until reaching the ground. B What is the maximum height above pre ground reached by the ball? C. What it the ball's velocity, metode and direction, as it hits the ground? D. What it the ball's totalte wine air as a projectile? E. How far horizontally does te ball travel in the air before hitting the ground? direction range -30-

Answer 1

b)

max height above ground

h = H + ( v sin x)^2 / 2g

h = 4 + ( 20 sin 42)^2/ 19.6

h = 13.137 m

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c)

velocity of ball just before hitting the ground

v' ^2 = v^2 + 2 g H

v' ^2 = 20^2 + 2 * 9.8* 4

v' = 21.872 m/s

direction of velocity

x = arccos ( v cos 42 / v')

x = 47.193 below horizontal

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d)

using motion along vertical

0 = 4 + 20 sin 42 * t - 0.5* 9.8* t^2

solving for t

t = 3 s

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e)

horizontal distance

D = V cos x * t

D = 20* cos 42 * 3

D = 44.59 m

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