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214e Questions and Problems the enthalpy change when 0.710 mol of calcium chloride dissolves in water? The solution process is CaCl2(s) Ca (aq) 2Cl (aq) 6.75 A sample of ethanol, C2HsOH, weighing 2.84 g was burned in an excess of oxygen in a bomb calorimeter. The temperature of the calorimeter rose from 25.00°C to 33.73°C. If the heat capacity of the calorimeter and con- tents was 9.63 kJPC, what is the value of q for burning 1.00 mol of ethanol at constant volume and 25.000C? The reaction is C2H5OH() 302 (g) 2CO2 (g) 3H2O(l Is equal to AU or AH? 6.76 A sample of benzene, C6H6, weighing 3.51 g was burned in an excess of oxygen in a bomb calorimeter. The temperature of the calorimeter rose from 25.00°C to 37.18°C. If the heat capacity of the calorimeter and con- tents was 12.05 kJPC, what is the value of q for burning 1.00 mol of benzene at constant volume and 25.00°C? The reaction is 15 Is equal to AU or 4H? Hesss Law Heat Capacity and Calorimetry

A sample of ethanol, C2H5OH, weighing 2.84 g was burned in an excess of oxygen in a bomb calorimeter. The temperature of the calorimeter rose from 25C to 33.73C. If the heat capacity of the calorimeter and contents is 9.63kJ/C, what is the value of q for burning 1.00 lol of ethanol at constant volume and 25.00C.

Is q equal to U or H?
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Answer #1

A sample of ethanol, C2H5OH, weighing 2.84 g was burned in an excess of oxygen in a bomb calorimeter. The temperature of the calorimeter rose from 25C to 33.73C.

If the heat capacity of the calorimeter and contents is 9.63kJ/C,

what is the value of q for burning 1.00 lol of ethanol at constant volume and 25.00C.

Is q equal to U or H?

formula
q calorimeter = C x ΔT

where,
C = heat capacity = 9.63 kJ/ºC


ΔT = (Tf-Ti) = 33.73ºC - 25ºC = 8.73ºC

So,
q calorimeter = (9.63 kJ/ºC) x (8.73ºC) = + 84.0699 kJ

q reaction = - q calorimeter

q reaction = - 84.0699 kJ


================================
"q for burning 1 mol of ethanol",


mol C2H5OH =
(2.84g C2H5OH) x (1mol C2H5OH/46.068g C2H5OH)
= 0.061648 mol C2H5OH

Now, q reaction / mol = (84.0699 kJ / 0.061648 mol)
= -1,363.71 kJ/mol C2H5OH
--------------------------------------...
What is the value of q for burning 1 mol of ethanol?

q = (1 mol C2H5OH) x (-1,363.71 kJ/mol C2H5OH)
= -1,363.71 kJ = -1.36371 x 10^3 kJ

= -1.36 x 10^3 kJ ---------------answer

=============================================

not equal

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