20A 20A 40A 20A Problem 4 Four wires of the same length are located 4cm from...

Question

Question

Answer 1

Answer #1

field due to long wire

B= μ *I / 2*pi*r

herr r= 4cm = 0.04 m

see diagram

2D 千 2. a 03 了

B_net in x = B2+ B4 = 4pi*10^-7*20 / ( 2*pi*0.04) + 4pi*10^-7*20 / ( 2*pi*0.04)

= 0.0002 T

Bnet in Y = B1-B3 = 4pi*10^-7*40 / ( 2*pi*0.04) - 4pi*10^-7*20 / ( 2*pi*0.04)

= 0.0001 T

so total B= √[ 0.0002^2+0.0001^2] = 2.23606798 × 10^-4 T answer

Good Luck

let me know in a comment if there is any problem or doubts

Answer 2

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