Question

A hydrogen atom is excited from its ground state to the n = 3 state. The atom subsequently emits two photons. Calculate the longer wavelength photon emitted. Value Units Submit Request Answer Part B Calculate the shorter wavelength photon emitted. MÅ O 2 ? Value Units Submit Request Answer

Answer 1

. For hydrogen atom, wavelength of emitted photon for transition - from mi state ng in AL - her hepatos - nel - RH [] RH ? Rydberg constant = 1.097x107/un for Hydrogen Energy and wavelength are related by de=ne = 40 a 5. So, for larger energy difference, shorter the wavelenght. since with increasing in the energy difference between two consecuritue n state decreases, so for transition from ground to n=3 exited state, tongett longest wavelength will be for n=2 to n=3 transition which has smaller energy differene. The shortest wavelength will be for n=1 to n=3 transition which has larger energy ere difference, - Shorter .. 8 tonger wave length - .. ni= ng =3. Ya ene CA 1094x10 *[ ^-+] = 102.55 x109 m 8 x 1,097 X107 : de = 102.55 nm > Shorter canelength 10 Longer Shorter wavelength - hi=2, nf = 3 To 1.097x10* [141] 36 5X1.097 x167 26.5633x10 7 m L = 656-33 x 177 m 2 656-33 mm y longer wavelength..