A tin surface emits electrons after shining with a light of frequency of 2.61×1015 s-1. Calculate the maximum kinetic energy of the ejected electron if the work function of tin is 4.09 eV.
Given:
Eo =4.09 eV
=4.09*1.602*10^-19 J
=6.552*10^-19 J
Given:
f = 2.61*10^15 s-1
use:
E = h*f
=(6.626*10^-34 J.s)*(2.61*10^15) s-1
= 1.729*10^-18 J
use:
E = Eo + kinetic energy
1.729*10^-18 = 6.552*10^-19 + kinetic energy
kinetic energy = 1.074*10^-18 J
Answer: 1.07*10^-18 J
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