Calculate H,0*] for a 5.32 x 10-M HBr solution. H,0+1 = x10 Calculate (H,0+) for a...

Question

Question

Calculate H,0*] for a 5.32 x 10-M HBr solution. H,0+1 = x10 Calculate (H,0+) for a 1.50x 10 ? M KOH solution. [H,0+) = X10 x1

Answer 1

Answer #1

1)

HBr is strong acid , so completely dissociates in water

HBr + H2O ------> H3O⁺ + Br^-

Therefore,

[HBr] = [H3O⁺]

[H3O⁺] = 5.32 ×10^-3M

2)

KOH is stong base , so completely dissociates

KOH -------> K⁺ + OH^-

Therefore

[KOH] = [OH^-]

[OH^-] = 1.50 ×10^-2M

ionic product of water, K_w = [H3O⁺][OH^-]= 1.00×10^-14

[H3O⁺] [OH^-] = 1.00 ×10^-14M²

[H3O⁺] × 1.50 ×10^-2M = 1.00 ×10^-14M²

[H3O⁺] = 6.67 × 10^-13M

Answer 2

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