Question

CW1-CO3 DETERMINE THE THEVENIN'S AND NORTON'S EQUIVALENT CIRCUITS OF THE FOLLOWING. 1. DETERMINE THE THEVENIN'S AND NORTON'S EQUIVALENT CIRCUITS. 5Ω 6Ω V ν a Vab ν: 10ν 2Α 20Ω b 2. 1ΚΩ 1ΚΩ να 2ν O 4ΚΩ 24A 4KSE ν b 3. 100Ω 150Ω Λ a να 24 200Ω Vab

Answer 1

1 w 52 M А 2or Vab 2A lov 20 Calculation of va b= Uth: KCL at A v-10 + = 2 => 4V1 t = 4 => 1 + 4 => $V1 = 4 => Vi= 16 th=,= 16 volt. Vi 20 20 20 284 Calculation of the 6n 52 a 2on Rth +6 Rtha (51/20+ 6 = 8X204 2755 = Tor Norton Current IN=&th = 16 - 1-6 Amp Thevenin equivalent :- Norton equivalent Rth a lor Elon lov 1.6A

Z 1K2 m aku mm VA NI T 4 kr vth (1) 24A 4K 8 20v Vith:- Voltage at node A = V. KCL at A, ~ - 24+ 4 V-20+ š=0 => V-20+* + š = 24 => VTV + = 44 => = 30.3 44 volt Uthaux 1 - 24.2752 volt. 4+1 1 Ко Rithe I kn mm 34kn AKR Rth eth Rth = [(a114) +1] 11 1.241 on 1,8114 =1-884. 1.8+ 4 24.2752 Amp = 19.555 Amp Rth 1.241 The venin equivalent Norton equivalent Isca Ith - a en 240 r a 1.2412 24.2752 volt 19.55 Amp b bb

3 3) 1 oor w 15on m t I 24U zoon I=o. Vaba Vith Vith V200 = Voltage acron zoon 16V. = - 24x 200 200+100 abz Vth= (150 x0) +16=16 volt. Rthi loon 1500 um o 2oor TRth Rtha (1001/200) +150 - 216.67 - IN= Vth = 16 0.0738 Amp. Rth 216.67 Thevenin circuit (equivalent) Norton equivalent eirmit ME 216.5tr Ta 6 volt 1. 216.670 b 0.0738 Arop