Question

Part 1 For your selected data set, calculate the following data statist Number of Data Values 59 Minimum Value 21 Maximum Value 1103 Mean Value 404.17 Median Value 350 Mode 291 Frequency of Mode 2 Range 1082 Quartile 1 250 Quartile 2 350 Quartile 3 543 Inter-Quartile Range 293 Sum of Data Values 23246 Sum of Squared Deviations 2820832.31 Standard Deviation (for sample) 218.66

Answer 1

groups of the following We have to organize the data into exactly 5 equal width. To find the width we will use formula Width 5 Range of dataset Number of class Range = - Maximum value - Minimum value 1082 (Giren in Part I calculation) Width = 1082 = 216.4 ř 216. We will start Grouping with first class as 21-237. 21 is lower limit of class since it is Minimum value in dataset & Upper limit is lower limit + class width. Class is better inclusive type of class ie It includes both upper & lower limit of class intaval. Similarly we will build an remaining classes. 27 Grouping Frequency Relative Frequency. 21 - 237 13/5g = 0.220 238 – 454 27/59 = 0.458 455 - 671 11/5g = 0.18% 672- 888 07/59 = 0.119 889 - 1105 01/59 = 0.017 이 To find frequency of class, count the values in data set that lie within the class interval (Consider upper & lower limit as well). 07 Total Frequency Total Frequency = 59 EN