Question

This is the code we have to edit, i know how to do everything except finding if the x and y are in the space, please explain to me when you do the code. We are using addshape() api and more.

public class Skeleton { public static void main(String[] args) { //================================ //== Setting up game window ====== SpaceGame myGame; //declaring the object form the class Scanner scan = new Scanner(System.in); System.out.println("What is the window name? "); //window title text String windowTitle = scan.nextLine(); System.out.println("Enter how wide you want the window to be: "); //window windowWidth int windowWidth = scan.nextInt(); System.out.println("Enter how tall you want the window to be: "); //window windowHeight int windowHeight = scan.nextInt(); myGame = new SpaceGame(windowTitle, windowWidth, windowHeight); //instantiation of the object. At this time, object is allocated in the memory (heap) //================================================== //== The following lines are to Add a spaceship ============= System.out.println("Where do you want your spaceship? (x and y)"); //spaceship location int spaceShipX = scan.nextInt(); //x coordinate int spaceShipY = scan.nextInt(); //y coordinate //To check whether the spaceship coordinates are inside of the game // window, what should we do? //TODO: Check whether the spaceship is inside the game window // If the spaceship coordinates are not inside of the window, // repeat by keep asking the user for coordinates until it is inside. //TODO: Now, add shape

Answer 1

int spaxeShipX;
int spaceShipY;
do{

   System.out.println("Where do you want your spaceship? (x and y)");
   spaceShipX = scan.nextInt();
   spaceShipY = scan.nextInt();
}while(spaceShipX > windowWidth || spaceShipY > windowHeight);

//So we will be reprompting the user until they enter valid x and y coordinates