Question

The vapor pressure of ethanol is

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1)

The vapor pressure of ethanol is \(1.00 \times 10^{2} \mathrm{mmHg}\) at \(34.90^{\circ} \mathrm{C}\). What is its vapor pressure at \(63.16^{\circ} \mathrm{C}\) ? ( \(\mathrm{AH}_{\text {vap }}\) for ethanol is \(39.3 \mathrm{~kJ} /\) mol. )

\(\mathrm{mmHg}\)

2)

Calculate the amount of energy (in kJ) necessary to convert \(457 \mathrm{~g}\) of liquid water from \(0^{\circ} \mathrm{C}\) to water vapor at \(187^{\circ} \mathrm{C}\). The molar heat of vaporization \(\boldsymbol{H}_{\mathrm{vap}}\) ) of water is \(40.79 \mathrm{~kJ} / \mathrm{mol}\). The specific heat for water is \(4.184 \mathrm{~J} / \mathrm{g} *{ }^{\circ} \mathrm{C}\), and for steam is \(1.99 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\). (Assume that the specific heat values do not change over the range of temperatures in the problem.)

\(\mathbf{k} \mathbf{J}\)

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Answer #1

B :/.oxlohm T,こ(34.90+23x 307.9 K 73). こ33616 k 3930D o 336-16k-3079k 307 k 3618 3 1, 2905 P2 1-2905 3.635 3635 x 10mm こ 2

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