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A block of wood (Mblock = 8.4 kg) rests on a horizontal surface for which the...

A block of wood (Mblock = 8.4 kg) rests on a horizontal surface for which the coefficient of kinetic friction is 0.4. A bullet (mbullet = 39 g) is shot along the horizontal direction and embeds in the block, displacing the block 82 cm.

What is the magnitude of the acceleration of the bullet and block from immediately after the impact until they come to a stop

What is the magnitude of the velocity of the bullet and block immediately after the impact?

What was the magnitude of the initial velocity of the bullet immediately before the impact?

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Answer #1

magnitude of acceleration = 0.4*9.8=3.92 m/s2

distance travelled before stopping = 82 cm = 0.82 m

velocity after impact = sqrt(2*3.92*0.82)=2.54 m/s

final momentum = 2.54*(8.4+0.039)=21.43 kg-m/s

mass of bullet = 39 gm = 0.039 kg

initial velocity of bullet = 21.43/0.039=549.6 m/s

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