A box (weight = 10N) is sliding down a track (y =1/x) from x=1 to x=2....
A box (weight = 10N) is sliding down a track (y =1/x) from x=1
to x=2. If the track coefficient of the friction is 
= 0.1, what is the value of fricitonal force at x=2?
Hint: consider the curvature of the curve at x = 2
Homework Answers
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A box (weight = 10N) is sliding down a track (y =1/x) from x=1
to x=2....
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In Figure 2, a block of weight W=100 N is sliding down a 2-stage ramp defined...
In Figure 2, a block of weight W=100 N is sliding down a 2-stage ramp defined by the angles a = 30° and B = 45°. The distances OA and OB are 2 m and 4 m respectively. The friction coefficient for the entire ramp is u=0.3. B Figure 2: System for Question 5. (a) Derive an expression for the component of the block's weight acting parallel to the 2-stage ramp (Hint: since the ramp has 2 stages defined by...
A 2 kg box is sliding towards the edge of a table. Its speed is 5...
A 2 kg box is sliding towards the edge of a table. Its speed is 5 m/s and it is 75 cm from the edge. The coefficient of kinetic friction is 0.3 for the box on the surface. You apply a tension force to the left. What is the minimum amount of tension needed to apply via the rope to keep the box from sliding off the edge?
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A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle ϕ=30∘ above the horizontal, as shown (Figure 6) . The normal force acting on the box has a magnitude n=1.7N, the coefficient of kinetic friction between the box and the plane is μk=0.30, and the displacement d⃗ of the box is 1.8 m down the inclined plane. What is the work Wfk done on the box by the force of kinetic friction?
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ii) Initially a 20.0 kg box is sliding at 1.26 m/s down an inclined plane that makes a 11.9° angle with the horizontal. If it reaches a velocity of 2.23 m/s in the same direction in 0.75 seconds and the coefficient of friction is 0.257, find the necessary applied force.
The weight of the box
The weight of the box is W = 90 N and thecoefficient of static friction between the boxand the floor is μ=0.65. Neglect the weights ofthe bars. What is the largest value of the force Fthat will not cause the box to slip?
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Determine the minimum weight W2 of block 2 to stop block 1 sliding down the incline. frictionless pulley Given the weight of block 1 W1 = 540 KN, the angle of the incline theta = 30 degrees and the coefficients of friction are mut = 0.17 and mu2 = 0.45 for blocks 1 and 2 respectively. W2 = Number Units (accuracy 1 kN)
Suppose you have to move a heavy crate of weight 875 N by sliding it along...
Suppose you have to move a heavy crate of weight 875 N by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 N, but friction prevents the crate from sliding. What is the magnitude Fp of the minimum force you need to exert on the crate to make it start sliding along the floor? Let the coefficient of static friction μs between the crate and the floor be...
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A 2 kg box is sliding down a ramp with a constant velocity of 0.7 m/s. What is the net force on the box? 10 N 1.4 N 20 N 0 N
17. A S2 N box is sliding down a ramp inclined at an angle of 30 with the horizontal at constant v diagram below velocity, as shown in the a. O n the diagram, draw the three force vectors acting on the box, including the weight, normal force, and friction force. Label each vector with its symbol, indicating force type b. Calculate the component of the weight acting parallel to the ramp. (2) Calculate the component of the weight acting...
Slanted surfaces with friction: A box is sliding down an incline tilted at a 12.0° angle above horizontal. The box is initially sliding down the incline at a speed of 1.50 m/s. The coefficient of kinetic friction between the box and the incline is 0.340. How far does the box slide down the incline before coming to rest? a) Draw Free Body diagrams for the two masses b) Write the equations for the two masses in the direction of motion...
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ii) Initially a 20.0 kg box is sliding at 1.26 m/s down an inclined plane that makes a 11.9° angle with the horizontal. If it reaches a velocity of 2.23 m/s in the same direction in 0.75 seconds and the coefficient of friction is 0.257, find the necessary applied force.
Determine the minimum weight W2 of block 2 to stop block 1 sliding down the incline. frictionless pulley Given the weight of block 1 W1 = 540 KN, the angle of the incline theta = 30 degrees and the coefficients of friction are mut = 0.17 and mu2 = 0.45 for blocks 1 and 2 respectively. W2 = Number Units (accuracy 1 kN)
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