Question

10. 0 ports SERCPIT 8.A.P.062. LV My roles Two window washers, Bob and Joe, are on a 3.00-m-long, 400-N scaffold supported by two cables attached to its ends. Bob weighs 880 N and stands 1.00 m from the left end, as shown in the figure below. Two meters from the left end is the 500-N washing equipment. Joe is 0.500 m from the right end and weighs 830 N. Given that the scaffold is in rotational and translational equilibrium, what are the forces on each cable? left cable C KN right cable C k N Joe Bob -1.00 m - 2.00 m- 0.500 m -3.00 m Need Help? Read It Watch It

Answer 1

Boon . V soon for 400N OE =3m OA - 1m OB = am, 00=2.5m =1.5m for translational equilibrium TR+ Ti = 880+400+ 500+830 TRATE = 2610 for to tational equilibrium about o Er =0 TR XOF) I (880X0A) + ( UOoxoc ) + + (SCOXUB) +(830XOD) 3TR = (880xl) +(400x1.5) + (500x2) + (830*2.5) 3 TR = 880+ Goot 1000 + 2075 3TR = u555 TR = 1518.34 = 1.51834 = 1.52kN T= 2610-TR = 2610-1518.34 TL 1091.67 1.09167 = 1.092 kn