Question

Please use detailed explanation/solution for problem

43* A student measures g, the acceleration of gravity, five times, with the results ll n mis 9.9, 9.6, 9.5, 9.7, 9.8.

Answer 1

The five measurements are: 9.9, 9.6, 9.5, 9.7, 9.8 so the average value = 9.9 + 9.6 + 9.5 + 9.7 + 9.8/5 = 9.7 Error in 1st estimate = mod 9.9 - 9.7 = 0.2 2^nd = mod 9.6 - 9.7 = 0.1 3^rd = mod 9.5 - 9.7 = 0.2 4^th = mod 9.7 - 9.7 = 0.0 5^th = mod 9.8 - 9.7 = 0.1 average error = 0.12 so the actual value in the range = 9.7 plusminus 0.12 = 9.7 plusminus 0.1 (a) So the Best estimate if the measurements is the mean value or the average value of all trials i.e,9.7 with uncertainty 0.0. (b) But the accepted value is 9.8 m/s^2. So it B higher than the Best value so % age of error = 9.8 - 9.7/9.8 times 100 = 1.02% for the Best value