Homework Answers
2 C10H22(l) + 31 O2(g) ---> 20 CO2(g) + 22 H2O(l)
DHrxn = (20*DHfCO2 + 22*DHfH2O)-(2*DHfC10H22 + 31*DHfO2)
= (20*-393.5+ 22*-285.8)-(2*-60+31*0)
= -14037.6 Kj
DHrxn = -7018.8 kj/mol
no of mol of C10H22 burned = 2.85/142 = 0.02 mol
heat released(q) = 7018.8*0.02 = 140.38 kj
q = c*DT
c = HEAT capacity of calorimeter = ?
DT = 22.7-19.5 = 3.2 c
140.38 = C*3.2
C = 43.87 kj/c
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