What is the mole fraction of phosphoric acid (H3PO4) in a 25.4% (by mass) aqueous solution...
What is the mole fraction of phosphoric acid (H3PO4) in a 25.4% (by mass) aqueous solution of the acid? Enter your answer with four decimal places and no units.
Homework Answers
25.4% by mass means
25.4 g of H3PO4 in 100g of aqueous solution.
Thus the mass of water in solution = 100- 25.4 =74.6 g
moles of H3PO4 = mass / molar mass
= 25.4g / 98g/mol =0.2591 mol
moles of water in solution = mass of water / molar mass
= 74.6g/ 18 g/mol = 4.14 mol
thus
mole fraction of phosphoric acid = moles of H3PO4 / moles of H3PO4 + moles of H2O
= 0.2591/ ( 0.2591+4.14)
= 0.0588
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