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(b) If R = 4solve and sketch the response of voltage, V(t) when t > 0. Next, obtain the current I flowing through the inducto

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Capacitor behave as open circuit when connected across 42 IH 0 I + 442 2 YV V(t) -0.25F svih ooh con no Equivalent circuit beTransforming the circuit is to taplace domain : 4/5 12/S -+ Us 24 + 12/5 I = 24 +3 -13 / utstys s = I= 12 +3 (52+45 +)/s »inverse laplace transform of I we get I= (3e-at + .6te 2t) A V = 4 = 4 x 1 + 1 x I +12 7 x 3 (sty) (5+2) 2 12 S all 12 (5+4)+30 25 20 +15 +10 5 0,5 1 1.5 2 7 2. 5 3,5 4,5 un 5,5

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(b) If R = 4solve and sketch the response of voltage, V(t) when t > 0....
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