null hypothesis: Ho: | σ2 = | 125 | |||
Alternate hypothesis: Ha: | σ2 < | 125 |
at 0.05 level and (n-1=19) df crtiical value= | 10.1170 | |||||
Decision rule:reject Ho if test statistic X2 in critical region: | X2 | < | 10.117 |
test stat : | =χ2=(n-1)s2/σ2=9*104/125 = | 15.808 |
as test statistic is not in critical region, we can not reject null hypotheiss.
we do not have evidence to conclude that researcher is justified that variance is less than 125
SAT test scores are reported to follow a normal distribution with variance 125. A re- searcher...
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13. Based on a random sample of size 20 from a normal distribution with variance o?, the width of the 95% confidence interval for o2 is 150. Let x2. be the the critical value of a chi-squared random variable with v degrees of free- dom. The following table lists values of xa, for specific combinations of a and v: v = 19 v=20 a= 0.975 8.907 9.591 a = 0.95a 1 0.117 10.851 = 0.05 30.144 31.410 a = 0.025...
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