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SAT test scores are reported to follow a normal distribution with variance 125. A re- searcher questions if the assumed varia

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Answer #1
null hypothesis:     Ho:         σ2 = 125
Alternate hypothesis: Ha: σ2 < 125
at 0.05 level and (n-1=19) df crtiical value= 10.1170
Decision rule:reject Ho if test statistic X2 in critical region: X2 < 10.117
test stat : 2=(n-1)s22=9*104/125 = 15.808

as test statistic is not in critical region, we can not reject null hypotheiss.

we do not have evidence to conclude that researcher is justified that variance is less than 125

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