Question

In the design of a building, you want to replace all the copper wiring (2000 m) 2.05 mm in diameter, with thicker Aluminum wire, so that the resistance of the wiring does not change. Considering resistivity, densities and prices: p [10-82m] 2.8 A1 Cu p[kg/m) 2,710 8,960 $ (usd/kg) 1.72 5.8 1.7 a) Calculate the diameter of the aluminum cable. b) Calculate the savings in USD that this replacement represents. c) Explain why, despite the savings, aluminum cables are not used as often for electrical installations.

Answer 1

@ for A : 1182 Same Resistance . RAL = Rec bla bla 2-8x66-8x 2000 TOR T 1.7x10-8x 2006 (2.05x103) 72 L 2.8 - xlosx10-6 7.7 V 821.315 mm d=28=2x1-315 da 2.631 mm diameter 1 of Aluminium . cable

2 6 Volume of copper a lengthy Ara V = 2000 x [T42,05x103)) 4 2 6, 598xio-3 m3 weight of copper auxe bin kg/m3 -8960x6.598x103 259.118 cost of copper - 59.118 x58 Cpr 342688$ volume of Al = lx A - 2000x [3-14% (esign the 20.01087 ms copper - UXP = 27108 0.01087 = 29.45 weigh af . Cost of Al= 29.45x 1.72 = 50.66 $ Savings in USD = C-C2 z 342.88 - 50.66 = 292.22

despite the as often they have also copper aluminium Savigns alominum cables are not used for electrical installations because less conductivity over copper and has better withstand load surges than