apply basic j query filter and highlight second and fourth elements with red boarder
Here is the code that you asked which was done by filter method and it is very basic.
the indexing start from 0 in jquery so we have taken odd positions.
index.html
<!DOCTYPE html>
<html>
<head>
<title>Filtering with jQuery</title>
<style>
.showOdd{
border: 1px solid red;
}
</style>
<script
src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("ul li").filter(":odd").addClass("showOdd");//selecting odd
positions(indexes) such as 1,3,5 so 1 represents 2nd element
$("p").filter(":odd").addClass("showOdd");//selecting odd
positions(indexes) such as 1,3,5 so 1 represents 2nd element
});
</script>
</head>
<body>
<h2>first example with list</h2>
<ul><!--first example with list-->
<li>First list item</li>
<li>Second list item</li>
<li>Third list item</li>
<li>Fourth list item</li>
</ul>
<hr>
<h2>Second Example with 'p' tags</h2>
<!--second example with p elements-->
<p>Welcome 1</p>
<p>Welcome 2</p>
<p>Welcome 3</p>
<p>Welcome 4</p>
</body>
</html>
Output screenshot:
Thanks, hope it helps to you.
apply basic j query filter and highlight second and fourth elements with red boarder
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