Question

Briefly discuss about the Miller Capacitance. Calculate the output network high-frequency cutoff of the given below FET amplifier circuit, if Cwo = X4 PF, Cds = 1 pF and Cgd = 0.5 pF, Voltage gain Av=-4 where x4 is the fourth digit of your student id [example if your student id is S0000001234, then X4 =4, hence X4 PF =4 pF] VDD 47 M2 4.7 k12 X 4 = 3 = OV 100 k12 0.1 uF 10 k2 0.01 uF mu Vsig 10 M2 2 k12 + 10 pF = IH H11 =

Answer 1

Co = wot cast cho 3P + Ipt 0.625P > Co= 4.625PF - output equivalent capacitance 4.7K X10K Rtho = (RO/URL) (4.7 K 1/10K) 14.7K Rtho = 3.197 kr where output higher cut off frequency is defined as fho 11 2 T R tho Co 21 (3.197K)(4,625p) Ifto = 10.76MHZ