Question

QUESTION 9 Given F(S) = 1/(5+1X5+3)) the fit) would be: A. None of the choices are correct B. Exponentially increasing C. Since the roots of F(s) are real and distinct, the time response would be real and constant D. Exponentially decaying E. Sinusoidal QUESTION 10 If in an RC circuit, the capacitance is increased by 25% and the resistance, R. is decreased by 10%, the time constant, A. Will be decreased by 12% B. Will be increased by 36.5% C. Will be increased by 13.5% D.None of the choices are correct . E. Will be increased by 12.5% QUESTION 11 Given (5) - 1/1(+15+3+J2X+3.2)), the f(t) would be: A. Exponentially decaying sinusold B. Sinusoidal C. Exponentially increasing D. None of the choices are correct E exponentially increasing sinusoid

Answer 1

F6 = 6:36+3) + (s+)(5+3) = = A(s+3) + B[s+1) SH)(s+3) Iz Ast3A +BS +B Compare s term Coefficient 0 = A+B - Compare Constant term 1 = 3A+B=(2 solving eqOq A = 0.5 B=-0.5 Fl) transform Apdly inverse Laplace flt) = 0.5ét -0.5237 option D

capacitance increased by es% q= c+0.250 G= 1.250 Resistance decreased by 10% Py = hroolr R = 0.gr Time constant e=QC = (.9R) (1.250) q = 1.125 RC increased by 12.5 % Time Constant option &

FIS) Fb) = (30) Statja) leta-ja) * (tu) (levo)- jakarta) itara) 4 (30) (5) (603) 4 (65) + - Bsto NI (5+3)+ (2) E A$$+3)+2) +(85 +c) (3+0) 15+(8+3) 29 (54) (5+3)+12):). :: 1 = A($+2+6+4) + Bs(s+1)+c(+1) r= A + 6AS+13A + B485 + este compare a term coefficient 0=A+B=0 compare a term Coefficient 0 6A+B+0 2

Compare Constant term Gefficient 1 = 13Atcy sowing 90,00 A= 0.125 Ba 20.125 co -0.625 FG) = 0.125 0.1255-0.625 . (5+3+ (2) 0.125 0.125$. -0.625 (st17 (5+3) + 125 (S124 125 F(s) = 0.125 - 0.125 (5+33) SH) -0.625 (BA) (5+3) + (2) (Stator . 112) Fis) = 0.125 +0.375 6.625 Els -25(043) +0.345 Totalt 65 (343) + len fbel et ses en torno 13+37 + 127 FS): 0.125 - 0 25 0.25

F(s) - 0.125 -0.125 (5+3) -0.25 - 25 2 , 2 (5+3)+(2)/ Als) Apply inverse Laplace transform FUE) = 0.125€ -0.1a5e* cos(zł) -0.125 € 3t sin lat)
option D