A cyclotron for accelerating protons has a magnetic field of 0.2 T and a radius of...
A cyclotron for accelerating protons has a magnetic field of 0.2 T and a radius of 1.6 m. The frequency of the cyclotron is?
Homework Answers
Fc = Fm
q*v*B = m*v^2/r
v = qBr/m
Now we know that
w = v/R
w = 2*pi*f
f = v/(2*pi*R)
f = qBr/(2*pi*r*m)
f = qB/(2*pi*m)
given values:
q = 1.6*10^-19 C
B = 0.2 T
m = 1.67*10^-27 kg
f = 1.6*10^-19*0.2/(2*pi*1.67*10^-27)
f = 3.049*10^6 Hz
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