Question

In Python

Write code that creates and prints a list by multiplying each number in the nums array by the number that precedes it. If there’s no preceding number, use zero in place of the preceding number. You could solve this problem serveral ways, but in this case, you’re restricted to using a for loop. You might have to create a temporary storage variable in your solution.

Using another for loop, print the elements with a comma between them.

Your output should look something like this:

0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342, 380, 420, 462, 506, 552, 600, 650, 702, 756, 812, 870, 930, 992, 1056, 1122, 1190, 1260, 1332, 1406, 1482, 1560, 1640, 1722, 1806, 1892, 1980, 2070, 2162, 2256, 2352, 2450, 2550, 2652, 2756, 2862, 2970, 3080, 3192, 3306, 3422, 3540, 3660, 3782, 3906, 4032, 4160, 4290, 4422, 4556, 4692, 4830, 4970, 5112, 5256, 5402, 5550, 5700, 5852, 6006, 6162, 6320, 6480, 6642, 6806, 6972, 7140, 7310, 7482, 7656, 7832, 8010, 8190, 8372, 8556, 8742, 8930, 9120, 9312, 9506, 9702, 9900, 

Answer 1

nums = [x for x in range(100)]

if len(nums) > 0:
    i = 1
    temp = nums[0]
    while i < len(nums):
        t = nums[i]
        nums[i] *= temp
        temp = t
        i += 1

    for i in range(len(nums)):
        print(nums[i], end='')
        if i == len(nums) - 1:
            print()
        else:
            print(', ', end='')