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On coordinate axes, point A = ( 1.50, 2.00), measured in meters. Let the voltage value very far away ("infinity") be defined as zero (ie. V-0). To make things simpler, just express your answers in terms of e and k (in other words don't plug in numerical values for e and k). A lone proton is placed at the origin a. Calculate the clectric field (magnitude and direction) it will cause at point A b. Calculate the magnitude and direction of the electric force it will exert on a proton located at point A Calculate the magnitude and direction of the electric force it will exert on an electron located at point A d. Calculate the uniform electric field (magnitude and direction) that would need to be present (in addition to the proton), so that an electron located at point A would have no accelcration. e. Calculate the electric potential (ie. the voltage) that the lone proton will cause at point A . Calculate the electric potential cnergy (U) that a second proton would have if located at point A g. Calculate the electric potential energy (U) that an electron would have if located at point A

Answer 1

a) Now the field of point a will be - E6vector = q/4 pi e_0 r^2 r^^= k = e/r^2 r^^where k = 1/4 pi e_0 where r^vector = 1.5 i^^+ 2 j^^and r^^= r^vector/ Vertical-bar r^vector Vertical-bar = 1.5 i^^+ 2 j^^/squareroot (1.5)^2 + 4 b) Now the force on the proton placed at a will be repulsive and the direction will be along r^^F6vector = k e^2/r^2 r^^c) Now the force will be attractive on the electron placed at A the direction of force will be along - r^^F^vector = -k e^2/r^2 r^^d) for no acceleration the force on the electron will be zero To make this the electron field will be E^vector = k e/r^2 r^^along r^^ \r\n e) partial will be v = l/4 pi e_0 r = k l/r f) Potential energy will be U_e = l^2/4 pi e_0 r = k l^2/r g) Potential energy will be U_z = -k l^2/r
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