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11. 0/1 points | Previous Answers | SCALCET8 13.2.033. / My Note ) and r(t) - (sin(t), sin(2), 41) Intersect at the origin. Find their angle of intersection, correct to the nearest degree The curves rit) - (5t, 2. 075 Need Help? Read Tato Tutor Submit Answer Practice Another Version

Answer 1

4,(t) = (st, t’, +3, (t) = < Sinct), Sin2t, 4t) intersection at (0,0,0) We have to find angle of intersection (0) bod we have to find angle of intersection in tangent direction in to we take derivative of given cueve lict) = {5, 20, 3+?), f(t) = <cost , 26052t, 4) &! (0) = <5,0,07 ri(t) = {1, 2,47 r. į, and to cut at oeigin (0,0,0) I hence x=st tol t = 0 y= z = +2 =0 t3 = 0 let 45,0,07 = u f {1,2,47 = V. Now angle of intersection is define by : UV coso - coso = sullul UV = Jul = 5x1 + 0x2 + 0x4 = 5 /1512 01+(0)2 = 5 lvl = 0+(21°+1412 - 21

Uov Tulvi coso e i Da Cost (m) - 0 = (os" (7.5825756 943 558 4.582 575 ( 94 9 SS8 70 = (05! (-2182178902359) → 0 = 77.395617351626 0 = 77 (nearest) A doubt please comment please like dag If you have any