Question

15. Two unusual dice A and B are constructed such that die A has the numbers 3, 3, 4, 4, 8, 8; and die B has the numbers 1, 1, 5, 5, 9, 9. If dice A and B are rolled, find the odds in favor that A beats B, that is, the number that appears on die A is greater than the number that appears on die B (A) 5/9 (B) 5/8 (C) 4/5 (E) None of the Above

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Answer #1

Sorry.. it was answered wrong due to technical error.

The possible outcomes for dice A is 3,4 & 8 with probabilty 1/3 each.

And the possible outcomes for dice B is 1,5 & 9 with probabilty 1/3 each.

Now, the Prabability that number appear on dice A is greater than dice B = P[ number appear on A is 3].P[ number appear on B is 1] + P[ number appear on A is 4].P[ number appear on B is 1] + P[ number appear on A is 8].P[ number appear on B is 1] + P[ number appear on A is 8].P[ number appear on B is 5]

= 1/3*1/3 +1/3*1/3 +1/3*1/3 +1/3*1/3

=4/9

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