A 5.06 10-5 H solenoid is constructed by wrapping 70 turns of wire around a cylinder with a cross-sectional area of 8.10 10-4 m2 When the solenoid is shortened by squeezing the turns closer together, the inductance increases to 8.22 10-5 H. Determine the change in the length of the solenoid.
inductance is given by L = u * N^2 * A/l
L = 5.06*10^-5, N = 70 , A = 8.1*10^-4
so l = 70*70* 8.1*10^-4/5.06*10^-5
l = 9.85 cm
l' = 70*70* 8.1*10^-4/8.22*10^-5
= 6.065 cm
so change in length = 3.785 cm
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