a)
n = 4.2 mol of Fe react
-1652 kJ accoridng to the Hrxn based on 4 mol
b)
when 1 mol is produced,
since the Hrxn is based in 2 moles:
1/2*Hrxn = 1/2*-1652 = -826 kJ
c)
1 g of Fe
mol = masS/MW = 1/55.5 = 0.0180
Q = n*Hrxn = 0.0180*(-1652/4) = -7.434 kJ
d)
12.5 g of Fe burn
mol = 12.5/55.5 = 0.22727
Q = n*Hrxn = 0.22727*(-1652/4) = -93.86251 kJ
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