Need this question answered in python.
from math import pi
def diameter(wireGauge):
return 0.127*(92**((36-wireGauge)/39))
def copperWireResistance(length, wireGauge):
d = diameter(wireGauge)
area = pi*d*d
ro = 1.678*(10**(-5))
return 4*ro*length/area
def aluminumWireResistance(length, wireGauge):
d = diameter(wireGauge)
area = pi*d*d
ro = 2.82*(10**(-5))
return 4*ro*length/area
# copy pastable link: https://paste.ee/p/oJptb
Need this question answered in python. Science P5.35 Electric wire, like that in the photo, is...
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