Question

identify the test statistic

identify the p-value

Save Score: 0 of 1 pt 3 of 12 (3 complete) HW Score: 16.67%, 2 of 12 pts (X) 8.2.9-T Question Help In a shady of the accuracy of tast food drive through orders, one restaurant had 40 is equal to 10% Does the accuracy rate appear to be acceptable? ders that were not cwale among 345 orders observed Use a 005 significance level to let the car that the rate of inaccurate orders

Answer 1

Solution: Given that, x= 40, n = 346 The sample proportion is, p=^ = 40 = 0.1156 Pan 346 Null and alternative hypothesis: H.:P=0.10 H:P+0.10 (Two tailed test) Significance level: a = 0.05 Test statistic: 2 -P P(1-P) Vn 0.1156 -0.10 10.10(1-0.10 346 = 0.97

P-value: p=2P(Z > Z) = 2[1-P(Zs)] = 2[1-0(0.97)] = 2/1 – 0.8340] = 0.3320 (Standard normal tables) Decision rule: Reject H,, if psa otherwise do not reject H. Since the p-value greater than the level of significance, so we fail to reject the null hypothesis at specified significance level. Conclusion: There is not sufficient evidence to rejection of the claim that the rate of inaccurate orders is equal to 10% It is plausible that the inaccuracy rate is 10%. This rate would be too high, so the restaurant should work to lower the rate.