Given Q 1 = 5 x 10 -6 C
Q 2 = 7 x10 -6 C
Q o = -3 x 10 -6 C
Potential at point A is V = [KQ1 / 14 cm ] +[KQ2 / 4cm] +[KQo/10.3 cm ]
= [KQ1 / 0.14 m ] +[KQ2 / 0.04m] +[KQo/0.103 m ]
Where K = 8.99 x 10 9 Nm 2/ C 2
Substitute values you get V = (321071 ) + (1573250 ) - (261844)
= 1632476 volt
Similarly
Potential at point A is V ' = [KQ1 / 16 cm ] +[KQ2 / 6cm] +[KQo/12.3 cm ]
= [KQ1 / 0.16 m ] +[KQ2 / 0.06m] +[KQo/0.123 m ]
Where K = 8.99 x 10 9 Nm 2/ C 2
Substitute values you get V ' = 280937.5 + 1048833 - 219268
= 1110502.5 volt
Potential difference = V ' - V
Answer both questions, multiple choice Two positive charges Q1 and Q2 are placed 10 cm apart...
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