Question

Question 2: (a) Derive the Trigonometric Fourier Series coefficients for the following periodic signal: ?(?) =...

Question 2:

(a) Derive the Trigonometric Fourier Series coefficients for the following periodic signal: ?(?) = |? ??? ?0?|

Hint: you may use the tringnometric form the F.S. representation.

(b) Compute the power contained in the DC component and the first 4 harmonics.

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Answer #1

the solution of part a:

cosine is considered to be period with an evaluation period for analysis form -pi to pi

ze (t) = ln Cos (wot) checking for even orodd X(-+) = la cos (-Cot) - la coswot) = 24) : so it is an even fonction - Cos vari

Calculation of Rota ao = f S xct) deert 207 + [ sua casa edest - facesat dent] * A [ 5a (608792 [sin(0] = [ (1-0) – (0-0) :

Calculation of an: C S211) cos nwot decot 9 [ So manas datuwd der faslatot ng = are 7 2 A[cos (tn),t) + Cos (v«n)Wet)dot -SA

- ZA cas que consum? - HA (as our) (*) an = the of (eraspt at n=1) an at nas put nal in an 0,3 ( sestose) - sa este det? x

brzo fourier Sales » a. t & an cosne + 3 bn cosma n Cosnat osna 0 X(+) - PA s S 4A Cos (NTT/2) Coscoot) TT i-n2).

the solution for part b:

power of the signal

P= 18(4)? dt

dc component power

power for Dc component 2 TT Pag can 1961 out - they r *(602)

harmonic component power

power of harmonics Par 514 se comuna *#14 em 1 | lesbianast best at a century as vos con leduct? 0 E UR

12 last 4 (14 los es)] * * { na celoten) (53 (1054) dent] * * { consomma[ (Side 15 as ant base] **{* ) 1 ( n + 4 column] 2coo

substituting in the above-derived equation

Pa2 = 0.09A2

Pa3 = 0

Pa4 = 0.0036A2

Pa5 = 0

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