Find the value of X if det [3 -7 2 x] = -7
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If A and B are 3 x 3 matricies for which det A = 2, det B =-2 find the following determinants: (all entries below are either integers or proper fractions in lowest terms) det(A)- det(B-44BA) = det(4(A(B-1)) detC4BT)-1) =
If A, B are 3 x 3 matrices such that det(AB-1) = 12 and det(A) = 4. Find 1) det(B) 2) det(AT. (3B)-1) 3) If A? + AB = { 1, find det(A + B)
3. Let det(A) = 3 and det B = –2. Find the indicated determinants: (a) det(AB) (b) det(B-1A) (c) det(AAT) (d) det(3BT)
9. Given det(A5x5)-3, find det(A3), det(5A), det(2AT), det(3A-1). 9. Given det(A5x5)-3, find det(A3), det(5A), det(2AT), det(3A-1).
9. [-14 Points) DET Consider the following. + 7x + 7; Find f'(x). f'(x) = Find F"(-1). f(-1) = Find the slope and an equation of the tangent line to the graph of the function f at the point (-1,-). slope equation y =
[i 1 -2] (a) Find det 2 3 5 by expansion along the 2nd row. (1 -1 3 (b) Use Cramer's rule to find the value of x in the solution to the system of linear equations shown below. (You may want to use your answer in part (a)). +y-2x = 0 2x + 3y + 5z = 3 2-y+32 = 0
(1 point) If A and B are 3 x 3 matrices, det(A) = -5, det(B) = 9, then det(AB) = det(-2A) = det(AT) = det(B-1) = det(B3) =
I need to find det (lambda * x - A): The determinant for this answer is: -x^3+7x-6. How can I get this answer? 8. (10 points) Find the general solution to the homogeneous system of DE: 3 2 6 x' = Ax where A = -2 -1 -2 -4) 1 -2
X and Y are n x n matrices and det X^T = 3 and B^-1 = 2 T F det(X^2 Y^2 (X^-1)^T) = 12 T F detX/(detY^T) = 6 T F det(X^3 Y) = 27/2 T F det(X^-1 Y^2 X ^T) = -4 T F det(X^-1 B^T) = 6 T F det(XY) = 3/2
[4 points Suppose A, B, and Care 5 x 5 matrices with det(A) = -2, det(B) = 10 and the columns of C are linearly dependent. Find the following or state that there is not enough information: (a) det(10B-) (b) det(AB) (c) det(CA+CB)