The magnetic force exerted on a 1.3 −m segment of straight wire is 1.5 N . The wire carries a current of 3.2 A in a region with a constant magnetic field of 0.49 T
What is the angle between the wire and the magnetic field?
use:
F = B*I*L*sin thetha
1.5 = 0.49*3.2*1.3 * sin thetha
sin thetha= 0.736
thetha = 47.4 degree
Answer: 47.4 degree
The magnetic force exerted on a 1.3 −m segment of straight wire is 1.5 N ....
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