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From the loading shown, determine the stress(es) at point A. Use the provided coordinate system. Also, determine the principl
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Guien [E = 450lb K 19.2 F · Neutral Aws My = 19.2 x 450 My = 8640 lb.in 192 8640*4 - 240 kpsi (Tensile) 12 (71) = ((-)). O(62) = Me (1) Mx = 0 Formula Z zu Pzu (69-79) Formula y7 here here has yr Y = 1 h=6 b=2 (Zuz=221) = 50 kpsi As so shear sso stress State At à Zau 6u = 240 Kisi Zuz = 50 kpsi principal stress G = P + J azén 6 = (2407+1 (40987 som (6 = 250 Apsi 22

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