True or False: During a titration the solution of UNKNOWN concentration should be placed in the...
KHP, potassium hydrogen phthalate (KHCHO is often used to standardie basic solution used in titration. If a 0.855. sample or KHP requires 31.44 ml of a KOR solution to fully realize it, what is the (KOH) in the solution? The reaction is KHC.H.O. KOHK C HO H O . 2. The KOH solution standardized above is used to titrate a 20.00-ml sample of sulfuric acid (H,SO.) solution of unknown concentration. Determine (H.SO.) for the unknown acid solution if 41.27 mL...
7. You are given a solution of unknown concentration of HCI. (8 Points) You are asked to determine its concentration by titration. You made up a 0.25 moles/Liter solution of NaOH. You filled the burette with NaOH up to the mark. You measured 10 mL of the HCl solution into an Ehrlenmeyer flask and added 1 drop of the phenol- phthalein indicator You titrated the HCl in the Ehrlenmeyer flask with NaOH from the burette 3 times. Your observations were:...
64 Experiment 9 Titration of an Acid with a Base QUESTIONS PRE LAB 1. How would the calculated concentration of the HCl be affected, if the sodium hydroxide were poured from a beaker that contained some water before the NaOH were added to it? 2. What color is phenolphthalein in acid? What color is it in base? 3. The acid and base in this experiment are completely harmless-True or False? Explain your answer.
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the equation H2SO4 + 2NaOH + 2H2O + Na2SO4 If you require 28.52 mL of 0.904 M NaOH solution to titrate 209.1 mL of H2SO4 solution, what is the concentration of the H2SO4 solution? Type answer:
In this experiment an EDTA titration was performed. Another common type of titration is an acid-base titration. Specifically, a neutralization titration can be used to determine the concentration of a strong acid if it is titrated with a strong base whose concentration is known. This method uses stoichiometry to determine the unknown acid's concentration. Let's say a student had 1.0 M sodium hydroxide ( a? ) and found a solution of sulfuric acid 2 04) whose label had faded. She...
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H2PO4 (aq) → Li3PO4() + 3 H20 (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (C) 11.40 M (d) 3.942 M
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H3PO4 (aq) → Li3PO4 (s) + 3 H2O (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M
18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) +H,PO, (aq) a Li,PO, (s) + 3 H20 (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M
DATA SHEET Overall Stoichiometric Equations 1. Results and Observations 2. Unknown No.:l Concentration of standard Na2S&O3 solution, M 0.020(0 Trial 3 Trial 2 Trial 1 13.22 33.97 o.0.20 1311 Initial burette reading, mL 13.09 Final burette reading, mL (0.21 Volume of NAS2O3 used, mL Amount of NA2S2O3 used, mol Amount of Cu2 in unknown sample, mol L0.00 10. 00 10.00 Volume of original Cu solution used, mL in original solution, M Concentration of Cu Average Concentration of Cu2, M Procedure...
To determine the concentration of a solution of sulfuric acid, a 125.0-mL sample is placed in a flask and titrated with a 0.1433 M solution of cesium hydroxide. A volume of 20.29 mL is required to reach the phenolphthalein endpoint. Calculate the concentration of sulfuric acid in the original sample. A student has 530.0 mL of a 0.1474 M aqueous solution of MnSO4 to use in an experiment. He accidentally leaves the container uncovered and comes back the next week...