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//Hi, I'm working on a function of a larger program that counts the number of leap...

//Hi, I'm working on a function of a larger program that counts the number of leap years through a wide range of dates. I'm told that both mathematical equations are accurate, but I // am likely using flawed syntax having an if statement inside of a for loop. Thank you for your debugging help.

#include <stdio.h>

int main()
{ int i, y=2000, numleapyears=0;
for(i=1;i<y; i++)
{
//Alternate equation
//if (((y%4==0) && (y%100!==0)) || (y % 400 ==0))
if ((!(y%4) && (y%100) ) || !(y%400))
{numleapyears++;}

}
printf("%d", numleapyears);

}

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Answer #1

Change ((!(y%4) && (y%100)) || !(y%400)) to ((!(i%4) && (i%100)) || !(i%400)) . y value is 2000. So, "if statement" condition will always be checked against same value(i.e., 2000). That is the reason for wrong output.

Here is the working code:

I #include <stdio.h> 3 int main() 4-{ int 1, y-2000, numieapyears-0; //Alternate equation //if if (((1%4--0) II (İX100 ! #-e)) Il 8 (i ะ-e)) && (1%100)) % 400 ((1(1%4) && !(1%400)) 10 numleapyears++;) printf(%d, num!eapyears); 12 13 14

output:

Please give thumbs up, if you like it. Thanks.​

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