Let Cm be the specific heat capacity of the metal.
We have:
Heat lost by the metal = heat gained by water
Hmetal = Hwater
mmCmΔT = mwCwΔT
(25 g) x (Cm) x (99 - 20.15) = (50 g) x (4.184 J/goC) x (20.15 - 14.37)
Cm = (1209.176) / ((25 g) x (99 - 20.15))
Cm = 0.6134 J/goC ----------- (**Answer)
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