Question

The figure on the left below shows a small lightbulb suspended at distance d1 = 250...

The figure on the left below shows a small lightbulb suspended at distance d1 = 250 cm above the surface of the water in a swimming pool where the water depth is d2 = 200 cm. The bottom of the pool is a large mirror. How far below the mirror's surface is the image of the bulb? (Hint: Construct a diagram of two rays like that of the figure on the right, but take into account the bending of light rays by refraction. Assume that the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin(?) apx.gif tan(?) apx.gif?.)
cm

hrw7_34-31.gif hrw7_34-03.gif
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Answer #1

so d = 250 + 400/1.33 - 200

d = 350.75188cms

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