Question

will rate

show good work plz

H= 9 m MWWWW dund

thats all i was given. plze just but a place holder such as 1or 2 for now thanks

Answer 1

I No. of Equipotential doops. [nd] : No. of Equipotential daops are & (16). Dischange. Q = K.H. ( N. Where Q = discharge k = co-efficient of permeability H = Head difference. Ne = No. of flow channel Nd = No. of Equadotential drops 2020.03.19 23:01

From the above problem Head difledence H = amu Nf = 4 a Nd = 8. Q = KH (Nf/na) = K*[9]*[ 26 ] = k* (4.5]. In the above problems the value of "k" Co-efficient of permeability is not givers, so that i am assuming value of K= 1 m/day. .: Q = kx (4.5) - 1x4.5 = 4.5 m/ day. 2020.03.19 23:02

17. poping Factors of sately for the Failure as E icsilical gradient ent gradied Giren data >- caitial gradient = lido dal Exitgradien = sh o e where sh = , L=width of the uppermont equipotential drop > L = 5m, -> H = am - Nd = 8 - sh = th d = 2/2 = 1.125 2020.03.19 23:02

E . Est gradient peut gradient = sh - 1.125 - 0.225 u. Factors of sately Csitical gradient F = 5 Eul gradient H1 TT 11 0.225 4.444 4.4 2020.03.19 23:02