Question

if a 100 kg sample of aluminum at 25.0 °C is heated with 500 kJ of heat energy, what will be the final temperature of the metal sample? The specific heat of aluminum is 0.897 J/ g• °C

Answer 1

$q = m S \Delta T$

q is the heat supplied (500 kJ or 500,000 J), m is the mass (100 kg or 100,000 g), S is the specific heat (0.897 J/g . C) and $\Delta T$is temperature change.

$500000 = 100000 \times 0.897 (\Delta T-25) \\ \Delta T = T- 25 = 5.6 \\ T = 30.6 ^oC$