Question

. Find the electric potential of the following configuration at point P. The two short sides of the triangle are the same size = 23 cm.

Q₁ = - 5600 nC

Q₂ = - 2200 nC

Q1 02

Answer 1

potential due to Q1 , V1 = k*Q1/r1

r1 = sqrt(23^2+23^2) = 32.5 cm = 0.325 m

V1 = -9*10^9*5600*10^-9/0.325

V1 = -155077 V

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potential due to Q2 , V2 = k*Q2/r2

r2 = 23 cm = 0.23 m

V2 = -9*10^9*2200*10^-9/0.23

V2 = -86087 V

V = V1 + V2 = -241164 V