Question

Experiment 4 Data Sheet Effect of Length The heavy mass and angular displacement of 5 are held constant. Cord Length, L (cm) Period, T (cm) Period' T' (sec) 20 60 80 100 Effect of Angular Displacemen The heavy mass and cord length of 100em are held constant Angle (°) Period, T (cm) Period', T (sec) Effect of Mass The cord length of 100 cm and angular displacements of 5° are held constant. Period, T (cm) Period?, T (sec) Wass eavy Mass ght Mass

Answer 1

To complete your table you should know the relation between these various terms that are used in this question ,The time period of a simple pendulum is given by , T = $\tiny 2\Pi \sqrt{l/g}$ . where g is the earth's gravitational acceleration , l is the length of pendulum.Now I will show you this by handwritten calculation.Here it is...
Effect of Length :- the mass is heavy and angular displacement is so are kept fined. . angle is small. ime perioe T = 20 ; 19= 980 cm/g2. in ca si Now by putting different l we can calculate it and fill the table. cord Length (1) Tom) o 20 40 Period, I (see) Period?, 72 (see) HT=&rx r g =0 T= 2T XV20=0.8976 0.8057. T = 2T* = 1.2694 1.6114 T= 25x160 80 = 1.55 47 2.4171 T-8T XV y = 1.7952 3.2227 T= 81 x The O = 2.0071 4.0284 go 100

Effect of angular displacement :- - A l=100 cm mass is constant. as T = at 1 %. (1+16 Time period for angle x 50 is modified 0²) [ neglecting I higher order Os angular displacement. "teomsT. Angle period, I (see) Period ² tr see2) have to T= 2* * o * [+46 1454 AM | = 91X0:319x[1+0.00769 4.0788 = 24x0.319 x 1,00762 = 2.0196 deg = 0.0175 radian o ko Ton 180 =0.175 4.2158 pox T=21*0.319 x [1+(0.175) = 24 x 0.319x1.0305 = 2.0654 E T=2X0.319x [1+(0.2625 15* 180 = 2x 0.319 x 1.0689 =0.262 = 2.1424 405900

Effect of mass : Mass is found to have no effect on the period.