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Need help with problem 5.44, help me understand, please explain in detail and write clearly. thanks in advance.

At section uid acts as 5.42 (See Fluids in the News article titled Bow Section 5.2.2.) The bow thruster on the boat shown in

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.44 kAZ 9310msf P200kfa and he We Linean the cemip enents un Uc momentum e deeine ompenent exeted ks reation n kee ewats foreCon sonuation 5.288 2 4 6.432 ms O 303 4 4 bocewe the ow mpamible Lernoul onle that we an ume alid henyghoat equali f demit gRx= 200, oo0 スズxt6XIOga x Y-2- 185000 N 6.32Xia 13o00 195300X - and +6.33x1o00X S.28 8 kN - 459 an ce -divetion Cempount4 fotplease rate and comment if doubt anywhere

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