Question

Imagine us cutting through a structural member to see the forces inside (we call these internal forces). In a ship-unloading operation, a 3500-lb automobile is supported by a cable. A rope is tied to the cable at A and pulled in order to center the automobile over its intended position. The angle between the cable and the vertical is 2 degree, while the angle between the rope and the horizontal is 30 degree. What is the tension in the rope? What is the tension between A-B?

Answer 1

let the tension in the rope is T , now we will take its components
TSin30 will be the vertical component and TCos30 will be the horizontal component.
HOrizontal component will cancel their effect and vertical will be add up.
Therefore
2TSin30 = 3500
T =3500 lb.
Now in the cable say tension is F
its vertical component would be FCos2 and that will be equal to the weight of the componet
FCos2 = 3500
F = 3502.133 lb