Question

Using the given data, calculate the rate constant of this reaction.

Image for Using the given data, calculate the rate constant of this reaction.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The reaction is A + B \rightarrow C + D

Let the rate law be r = k [A] m [B] n    

From the table the rate law for the three readings will be as follows:

reading (1)    ------> 0.0153 = k (0.340 ) m (0.240)n                          ------------------------- (1)

reading (2)    ------> 0.0809 = k (0.340 ) m (0.552)n                          ------------------------- (2)

reading (3)    ------> 0.0245 = k (0.544 ) m (0.240)n                          ------------------------- (3)

Eqn (3) / Eqn (1) becomes \frac{0.0245}{0.0153}=\frac{k(0.544)^{m}\left ( 0.240 \right )^{n}}{k(0.340)^{m}\left ( 0.240 \right )^{n}}

                                     1.6= 1.6^{m}

                                               m = 1

Eqn (2) / Eqn (1) becomes \frac{0.0809}{0.0153}=\frac{k(0.340)^{m}\left ( 0.552 \right )^{n}}{k(0.340)^{m}\left ( 0.240 \right )^{n}}

                                     2.3= 2.3^{n}

                                                  n = 1

So rate law becomes r = k [A] 1 [B] 1    

                              r = k [A][B]  

Substitute the values of r, [A] & [B] from reading (1) we get

          0.0153 = k (0.340 )1 (0.240)1

          0.0153 = k (0.340 )(0.240)

                  k = 0.1875 M-1 s-1

Add a comment
Know the answer?
Add Answer to:
Using the given data, calculate the rate constant of this reaction. Using the given data, calculate...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT