Four small aluminum spheres form the corners of a square whose
side is 1.7 cm long. A fifth iron sphere is in the center of the
square. m1 = 450 g
m2 = 110 g
m3 = 250 g
m4 = 450 g
m5 = 560 g
1)
What is total gravitational force on the fifth sphere in the y-direction?
N
2)
What is total gravitational force on the fifth sphere in the x-direction?
N
3)
What is magnitude of the total gravitational force on the fifth sphere?
Four small aluminum spheres form the corners of a square whose side is 1.7 cm long....
In the figure, a square of edge length 21.0 cm is formed by four spheres of masses m1-5.30 g, m2 -2.60 g, m3-1.20 g, and m4 = 5.30 g. In unit-vector notation, what is the net gravitational force from them on a central sphere with mass -2.20 g? m5 mg m4 j Units Number
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